Is it possible to get the Display Buffer into a Floating Tile?
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@Christoph-Hart How is the inverted plotter supposed to work? I was assuming that a plotter would set the value at the bottom of the panel to 0 and draw upwards, and an inverted plotter would set the value at the top of the panel to 0 and draw downwards.
I'm not seeing any difference when I change the START and use drawPath.
g.createPath(area, [0,1,0,-1], 0.0);
g.createPath(area, [0,1,0,-1], 1.0);
I AM seeing a difference if fillPath:
g.createPath(area, [0,1,0,-1], 0.0);
g.createPath(area, [0,1,0,-1], 1.0);
The question: Is this the way it's supposed to work? If so, how can I invert the value of a display buffer so I can start drawing at the top of the panel?
// Oscilloscope: d.createPath([0, 0, w, h], // target rectangle [-1, 1, 0, -1], // samplerange 0 - numSamples, // valuerange: from -1 to 1 0.0); // start at the center (bipolar) // Plotter d.createPath([0, 0, w, h], // target rectangle [0, 1, 0, -1], // samplerange 0 - numSamples, // valuerange: from 0 to 1 0.0); // start at the bottom (unibipolar) // Inverted Plotter d.createPath([0, 0, w, h], // target rectangle [0, 1, 0, -1], // samplerange 0 - numSamples, // valuerange: from 0 to 1 1.0); // start at the top (negative)
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@Dan-Korneff Seems to work if you just flip the height to be a negative value:
var p = gr.createPath([a[0], a[1], a[2], -a[3]], [0,1,0,-1], 0.0);
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@ustk You're hired!
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@Christoph-Hart I need to increase the buffer size to about twice what's available to the Plotter. Can I just change this:
return SimpleRingBuffer::withinRange<4096, 32768 * 4>(v) && wasPowerOfTwo;
to:
return SimpleRingBuffer::withinRange<4096, 32768 * 8>(v) && wasPowerOfTwo;
Or will this blow up??
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So far, no explosions
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@Dan-Korneff I imagine the only issue would be that a longer buffer would require more time to create a path, but if it can be noticeable I don't know :man_shrugging:
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@Dan-Korneff @ustk It seems interesting. Can you guys share a basic fast snippet for this please?
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Bump please
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@JulesV Here is a custom node example. After adding a display buffer to the custom node and compiling it, you need to open this node in
HardcodedMasterFX
and apply the following method. To get the look I wanted here, I had to keep the buffer length quite high, it's set to 65536 :)The drawing process takes place in a timer object.
const var dp = Synth.getDisplayBufferSource("HardcodedMasterFX"); const var gr = dp.getDisplayBuffer(0); gr.setRingBufferProperties({ "BufferLength": 65536, "NumChannels": 1 }); const var Panel1 = Content.getComponent ("Panel1"); const var a = Panel1.getLocalBounds(0); const var Cmpt = Engine.createTimerObject(); Cmpt.setTimerCallback(function() { Panel1.setPaintRoutine(function(g) { g.setColour (this.get("bgColour")); g.fillRect(a); g.setColour(this.get("itemColour")); var p = gr.createPath(a, [0,1,0,-1], 1.0); g.fillPath(p, a); }); }); Cmpt.startTimer(40);
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@orange is there some reason you are declaring the paint routine in the timer and not outside it, then issuing a repaint in the timer?
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@Lindon Not a specific reason, I just used the time object to refresh the paint.
If you have a better usage recommendation instead, I'm open to it. -
@orange well clearly I havent tried it, but give this a go and see if it works?
const var dp = Synth.getDisplayBufferSource("HardcodedMasterFX"); const var gr = dp.getDisplayBuffer(0); gr.setRingBufferProperties({ "BufferLength": 65536, "NumChannels": 1 }); reg p; const var Panel1 = Content.getComponent ("Panel1"); Panel1.setPaintRoutine(function(g) { g.setColour (this.get("bgColour")); g.fillRect(a); g.setColour(this.get("itemColour")); p = gr.createPath(a, [0,1,0,-1], 1.0); g.fillPath(p, a); }); const var a = Panel1.getLocalBounds(0); const var Cmpt = Engine.createTimerObject(); Cmpt.setTimerCallback(function() { Panel1.repaint() }); Cmpt.startTimer(40);
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@Lindon Thatโs better, thanks :)
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@orange glad that it worked...
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