Help with getCallWith

[Christoph Hart]

@Lindon yes

[Lindon]

@Christoph-Hart cool.

[Dan Korneff]

Can you guys give me a hand with a simple POST request? I probably need a tee-shirt, but I can't see what I'm doing wrong.
In short: I'm sending my name to a php script, and I'm expecting to get a response containing a status and message formatted in json.
My php code looks like this:
https://www.mytestserver.xyz/testing/simple-response.php

<?php
  // check if form has been submitted
  if (isset($_POST["name"])) {
    $name = $_POST["name"];
    // create response array
    $response = array(
      "status" => "success",
      "message" => "Hello, " . $name . "!"
    );
    // return response as JSON
    header("Content-Type: application/json");
    echo json_encode($response);
  } else {
    // return error if form has not been submitted
    $response = array(
      "status" => "error",
      "message" => "No name provided."
    );
    header("Content-Type: application/json");
    echo json_encode($response);
  }
?>

If I navigate to the page, I get an expected response:

{
"status":"error",
"message":"No name provided."
}

If I use postman.co and enter in some key data, I get an expected response:

My HISE script looks like this:

HiseSnippet 928.3ocsVs0aaaCElxIbnR6BVA5dWvOo.3lXu01MzhgkYGmMikKFQoc6sBFJ5HhPQpQRkUsg7WZ+11+fsCkjsjyb6JLV8CB3b+67QdNzy0JJyXTZjm+kk4Lj2mfiKk1zIoDtDM6Hj2Wf+wYwSCOgSYRCKLtzXYYnwk4Digkf7714Gbt54uKp52e8ciIBhjxZUgPuRAgeBOiaa0N+vehKDGSRXWxy538SNbFUImnDpB.V6fGhxIzaHWyNi3bqGF48QSS3VkN1RrLCxa2wpjx3T0uIq8+UbC+JAyILBECIpV8wJQhCwNsnIobQx7ksuAAYYdKYrSMY7H7o7D9J8sjxmWYHrMht7gWu0g2NqAuQcg2vNvaCPxqCj1sFRODGS07baqEGd9X7LokoWP.ZuKTp8E06O6gmn.Oj18yH2vNVCBqhH5YCGNHD9r2KBBhY5aY58ML6Xhg8xKNIpep0lad9AGjUBsi0T6vaJ+8C5CA.GUFa3sDc33BqUIGE9sgKK00L6DUVtRBBQ8ar6BJHfKEbIKbQgjZ4JYngmkKXWv90BnDQ6E7GA9BEkHByIZ3XGPJj2.ePseeInn+yC6aSAhzjUVIG3e2KB7C7avODp3m41z4mGeYTeGt4xqOntJOVyL.nLr8ySy6OnsDCVgmHCb1UXFDtz08pqMzYFk.BTygVxpcr2JWfFy+N3ycapAUxl92QNZkHhtjYF.rmnfU0y7EQMBUk6drhK+AUo++fgcGeM0YBPDWAyOQ2G.P15.tyTV14xZhO3tfv6aZwhMZqIWBldilcC152UfQxhrqbDeKE3bDtsu9HD9sOB0cBmVSKcbTImI41yyYx21bOpgKciaMnBb0VMr8YMCa0LGhCyT93FZDUA4tK4Pub1QDKYYhfbB0ImosbWK3cD6VXIX8TrO9Hl4FqJux2lCPnMeOJ6aVUxv7CKaq+hC4lSUYPdH5xll8eu9.VboRJDD65aybqvaL.mOqsBwslPZ31xtq3+eaE26KDeHdN2RS2LF6sALBmBeHvXyCCeJd5hELpsEf6hO9W9v7J.5BUga60oDqlCm93yJxhg2FoLn5RIS3lO754tIWKOzI6XfXlLoR3ugeMFG4j8ZLNZoQTFgpUulVe+28zyCpz.XRV8pqO9Tmb3pq8X7v8GhxfWAeMk5Z+GC221bLe4VDyWsEw7jsHlmtEw7rsHludKh4admw39CHeegUkUON.JlOsZ8im2TIAtYUcKD8O0FDwOB

Server.setBaseURL("https://mytestserver.xyz/");
const var Button1 = Content.getComponent("Button1");


inline function simpleRequest()
{
	local parameter = 
	{
		"name": "thisismyname"
	};
	
	Server.callWithPOST("testing/simple-response.php", parameter, function(status, response)
	{
		Console.print(trace(response));
	});
};


inline function onButton1Control(component, value)
{
	if(value)
	{
		simpleRequest();
	}

};

Content.getComponent("Button1").setControlCallback(onButton1Control);

The response is timing out

I'm sure it's something simple that I'm overlooking. Anyone see an issue?

[d.healey]

I think you need to use the return keyword to get the value, and just return the array, don't use json_encode.

[Dan Korneff]

@d-healey instead of echo?

Trying that, I get this error when I navigate to the page in a web browser:

SyntaxError: JSON.parse: unexpected end of data at line 1 column 1 of the JSON data

And there is no change when I try in hise

EDIT: just re-read your reply. Trying that now.
ok tried

<?php
  // check if form has been submitted
  if (isset($_POST["name"])) {
    $name = $_POST["name"];
    // create response array
    $response = array(
      "status" => "success",
      "message" => "Hello, " . $name . "!"
    );
    // return response as JSON
    header("Content-Type: application/json");
    return $response;
  } else {
    // return error if form has not been submitted
    $response = array(
      "status" => "error",
      "message" => "No name provided."
    );
    header("Content-Type: application/json");
    return $response;
  }
?>

Getting the same syntax error. I believe "return" only works within a function

[d.healey]

@Dan-Korneff

Getting the same syntax error. I believe "return" only works within a function

Ah yeah that's right. I didn't notice it was outside a function. Try putting it in a function, see if it makes a difference...

[Dan Korneff]

@d-healey does this look right?

<?php
function simpleResponse()
{
    // check if form has been submitted
  if (isset($_POST["name"])) {
    $name = $_POST["name"];
    // create response array
    $response = array(
      "status" => "success",
      "message" => "Hello, " . $name . "!"
    );
    // return response as JSON
    header("Content-Type: application/json");
    return $response;
  } else {
    // return error if form has not been submitted
    $response = array(
      "status" => "error",
      "message" => "No name provided."
    );
    header("Content-Type: application/json");
    return $response;
  }
}

echo $response;
?>

Not working here

[d.healey]

@Dan-Korneff Where are you calling the function?

[d.healey]

Actually forget about that. I just tested on my localhost and your original code works here.

I modified it slightly but I don't think it makes a difference.

<?php
  // check if form has been submitted
    $response = [];

  if (isset($_POST["name"])) {
    $name = $_POST["name"];
    // create response array
    $response = array(
      "status" => "success",
      "message" => "Hello, " . $name . "!"
    );
    // return response as JSON
    header("Content-Type: application/json");
  } else {
    // return error if form has not been submitted
    $response = array(
      "status" => "error",
      "message" => "No name provided."
    );
    header("Content-Type: application/json");
  }
  echo json_encode($response)
?>

[d.healey]

Oh I see your mistake (I think) you are missing www. in your url.

[Dan Korneff]

@d-healey My hero!!! that was it