Inline function triggered by a callback = execution timeout
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@ps can you reproduce the timeout with a dummy loop that does nothing instead of findFiles (eg calculating 100000 sin values?
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@Christoph-Hart ok it seems the loop itself is pretty unrelated.
I can also get the timeout with find files in the function and a random loop generating Numbers. The moment I comment out find files.. no timeout.The following executed by the response callback is enough to break the script - if find files function is in there I'll never see the beautiful numbers in the console.
BTW not it doesn't matter anymore if it actually finds files. Before that I was looping through the results - so no results no loop iteration.I can EITHER remove the Paint Routine or the FindFiles line to execute the loop
inline function test() { local files = FileSystem.findFiles(FileSystem.getFolder(FileSystem.Samples),"*.anything",1); for (i=0;i<100;i++) { Console.print(Math.random()); } }
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It works fine here on my Mac. @ps What Mac are you using?
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@d-healey said in Inline function triggered by a callback = execution timeout:
It works fine here on my Mac. @ps What Mac are you using?
--its broken here on my PC too - so its not a mac issue.
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@Lindon @ps Just to confirm we're all doing the same test, here is the snippet I'm using, constructed from ps's code.
HiseSnippet 1170.3ocsV01aaaCDlJIpnVacXEX+.H7mjWbcr255FVVwpisbh5rkDrjqWwvPAqDsMWjHMDoSqwP96ree6C66aGk7aYIHq0.S.1R2a7t64NdjA4hXpTJxQFUhVNmhL9Tyvkb0rNyHLNxsKx3yLGPjJZNtj0YKmSjRZBxv3vy0LLpbDp34O+wyHoDdLcKKD5UBVLsOKio1xM3E+DKMsGIgFwx1Q6m9B2XAuiHUr.hmCMahlShujLk5QzpcfIx3ANILkHOTQTTInyYhjkgyDuiWp+qXR1aSoZhVnPXgJYi5LiklDrNWkHjwQAay7CKy7uvb.Kgsg+VD3yKDf2ZwtXfwA2WH05iHjL1IjNpLjdrYXbNatZqDc77IltbnfLg.P8tgRotnC9qCM6H.M3pFYjKo8xAhMVX+rlMqig+pcpk0ImbBt2HuNQt9d3Ns62206bba7KCAxiwCcBC78BcvQCcO+bmgg31d9QW3LD65AZ5rwTKKFOkwo3IK3wJlfiSEjjeSxsqY86VUBo4WQyaHopyHR5ng8sqNSolK+9SNQJxnpYL9zFwhrpPHUYi5wjzzwL0rychrqtUwp0wUgeq8jsDv8Ex53bpbtfKo0rp.tDWAJFJ6ZmhwVUtt1oUrt1xZSPsJygLwAO1A643zEC4EtmqWW3u9NgaQErsaDdb6P7KGEFAXSG+QA8cVoEHusGNLraM.t54OD222O.Vp1Q3fQgW.Z35E4Wr1sGNr8qwtgEdC7Grhic52+1PWYfqwsTAfA3IrTpD+bbO3c3RXmXViILdhlTZuCyoTUOQZBMeWlgjr4fd0.P6KaP3KWCgsJg5Ih7J1rm27TL6GZ0T+53iKAvJPGjTjRaLOmwU1CHpYMxI7DQlcMssWqAT.D63O.fiHm9uFOxanS+1QPtEzFRa7P+QQ5tjmf8.HvcfCPiGegCzo4OXfimVSfkkEroWpvWQxwADNMsEjrq6egjpiHCJr.gc0Rw51DqxO08TAv1T0PwBEfh1aZKlVffSajjSdW6T1TNMIh9dXMh.3E.feoY8l0AzPpcwXVhZlcsMzWPYSmAEgeEfsXvy4zjpE8P0NcSYRv8DJp+pVb.Mv+aQSlbmxzoVtHMEJT2kX8Hw76yPa9hr2RyqC.V5B5FEgYF2bPzC9vFDEWhz6nnf6xYJ+4zUzEcUIkee6wVnUkJ3qQtcIJhdR1Jdfdyo4JlNbL5RuBNJnbtVEytT4kJw7BcWUegLPUH8Qqm5oqwHF35GZVVuQuGYXZXYfPK0e7GEmlbqolv7ZQxhTh5lCw0mVsR..n2Xxod5HWxTK28zrOhI6Mu2I6eng3iMCXp3Y2cLdvcDi.T++QLt57vGY5LYBMVsM.Oxr2OuuG98e39xMvSg4L4LcQ1aQVHbMfXJ3cNT5k558A51sR5lZZMBDR4IED+M7rRXKMswJgsVKDkQhyEuItbaj9D2GVvAhIdwELp.2zAnwsPEas.6La1nIJCN7+Mww5z+IvNf61luZOr4q2Cad5dXy2rG17r8vlucOr46tWaz26p8BkHqb6.vHvoXFiggCm.cVEcgn+Afiwlu+
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Ok just to get a little bit more systematic:
- both macOS / windows
- only the
findFiles()
call is affected. Using a loop to simulate a heavy task doesn't trigger. BTW, you can useConsole.startBenchmark()
andConsole.stopBenchmark()
before and after the loop to find out how long it takes. Try increasing the loop count until the timeout happens and then let me know what's the value that is causing the timeout (it definitely triggers the timeout after a certain period of time). - it happens only if the findFiles() call is happening in a callback. Does it also happen with
Engine.showYesNoWindow()
? This is the most simple callback to reproduce.
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As far as I could reproduce only findFiles() in combination with a loop in the same function leads to timeout when executed by a callback.
But this is getting stranger and stranger. In the meantime I cleaned the build directory - compiled a plugin and after that tried my little dummy code again. Suddenly no timeout (At least not every time... before that it was a sure thing). Once I push the loop harder (1000 instead of 100 values) it's back again. (unless I remove find files or the paint routine). Also in larger projects it seems to be related to the workload of the function somehow.
Where should I place the Console.stopBenchmark() because when I get the timeout it never reaches the stop point.
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@ps How many files are in the folder you are scanning with
findFiles
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Where should I place the Console.stopBenchmark() because when I get the timeout it never reaches the stop point.
Remove the findFiles call, then put the
stopBenchmark()
call after the loop and play around with the loop length to find the spot where it times out. Then check what value it prints for the highest loop count you can get it to run through. -
@d-healey I tried different locations with different amounts.
I just searched through 3 big folders taking 300ms without a loop no problem - adding just a dummy loop printing 10 numbers - timeout
and again removing the paint routine - no problem for the full function at all
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@Christoph-Hart without the find files function I can torture it about until 5.5mio random numbers taking around 5seconds.
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@Christoph-Hart ok wow I just realized I had commented out the paint routine - now that I have the paint routine back in I can only get a fraction of that.
With paint Routine in the script I can make it to 300ms (Yes not seconds) until the timeout
Starting not from the Callback but just calling the function on init I can go up to 5seconds with the paint routine as well
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Just to note I was also seeing this in functions that were using the .getUserPresetList()
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@Lindon do you mind trying if the following code in an otherwise empty script is affected by the fact that the paint routine is commented out or not? Just try what benchmark you can hit with paint routine in and out.
As said for me it's worlds between it just because of the fact that the script contains pr./* const var Panel1 = Content.getComponent("Panel1"); Panel1.setPaintRoutine(function(g) { g.drawAlignedText("Test", [0,0,this.getWidth(),this.getHeight()], "centred"); }); */ inline function loadjsn() { Server.setBaseURL("https://something.com"); Server.callWithGET("/something", "", function(status, response) { test(); }); } loadjsn(); inline function test() { Console.startBenchmark(); Console.print("start"); Console.startBenchmark(); for (i=0;i<2000000;i++) { Math.random(); } Console.stopBenchmark(); }
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@ps well with the paint routine out and then wiht it in:
Interface: start Interface: Benchmark Result: 194.833 ms Interface: Compiled OK Interface: start Interface: Benchmark Result: 193.293 ms
Yeah quicker (just) with it in...
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@Lindon haha but can you also push it to the same values by raising the number in the loop until you get a timeout?
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@ps said in Inline function triggered by a callback = execution timeout:
@Lindon haha but can you also push it to the same values by raising the number in the loop until you get a timeout?
yep got you -- set the loop to 9000000 works fine with no paint routine, fails with a paint routine:
Interface: Benchmark Result: 864.576 ms Interface: Compiled OK Interface: start Interface:! Line 30, column 9: Execution timed-out {SW50ZXJmYWNlfHw1MzB8MzB8OQ==} extimeout:! Line 30, column 9: Execution timed-out
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@Lindon ahh thanks for confirming - I assume that also on your end probably it’s around 300ms with the paint routine (which makes the find files function and other functions that need a bit more time run into timeout)
So the question is - why does including a paint routine limit the timeout to such a short time when an inline function get’s called through a callback…
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@ps said in Inline function triggered by a callback = execution timeout:
@Lindon ahh thanks for confirming - I assume that also on your end probably it’s around 300ms with the paint routine (which makes the find files function and other functions that need a bit more time run into timeout)
So the question is - why does including a paint routine limit the timeout to such a short time when an inline function get’s called through a callback…
damn good question..
I've got it paired down to this and it errors...
inline function test() { Console.startBenchmark(); Console.print("start"); Console.startBenchmark(); for (i=0;i<2050000;i++) { Math.random(); } Console.stopBenchmark(); }```
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@Lindon which is based on your benchmark before not a very long time probably - I guess this is a case for @Christoph-Hart now :)