LFO Shape Designer
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@d-healey so push and remove might help here I guess....
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@d-healey or concat
Making some (slow) progress... please let me know any pointers if you have any... :folded_hands:
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@d-healey ok so I have figured out some of the permutations of drawing tables with the array and joining two or more arrays.
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I'm now wondering how to make the x/y/curve values inside the array to be dynamic. So if I do, for example:
reg x1 = 0.255; const var newShapeArray2 = [[x1, 0, 0.5], [0.375, 1, 0.5], [0.376, 0, 0.5], [0.376, 0, 0.5]] inline function onshape2Control(component, value) { local newShape = []; x1 = 0.355; newShape.concat(flatArray, newShapeArray2); tableShape1table.reset(); tableShape1table.setTablePointsFromArray(newShape); }; Content.getComponent("shape2").setControlCallback(onshape2Control);
... the array doesn't update the value of x1 - because the value is set on oninit. So can you update / refresh the array before calling it? Or maybe I need to clear it then push it?
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@DanH said in LFO Shape Designer:
So can you update / refresh the array before calling it?
It's just like any other variable, you can change the value whenever you like
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@d-healey Ok well in this case I can't figure out a neat way to do it... Any ideas?
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Before you concat the array, assign your new x value.
Something like
local newShape = []; x1 = 0.355; newShapeArray2[0][0] = x1; newShape.concat(flatArray, newShapeArray2);
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@d-healey said in LFO Shape Designer:
newShapeArray2[0][0] = x1;
what does this line do? Why the [0][0]?
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@DanH You have arrays inside an array. We are accessing the first element of the first array.
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@d-healey Got it, thanks :)